14k^2+168k=0

Solution for 14k^2+168k=0 equation:

14k^2+168k=0

a = 14; b = 168; c = 0;
Δ = b2-4ac
Δ = 1682-4·14·0
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-168}{2*14}=\frac{-336}{28}
=-12
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+168}{2*14}=\frac{0}{28}
=0
$